berapa gram massa dari 0,6 mol glukosa c6h12o6
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Jawaban:
108 gram
Penjelasan:
[tex]n \: = \frac{g}{mr} [/tex]
mol glukosa = massa glukosa ÷ Mr glukosa
massa glukosa = mol glokosa × Mr glukosa
Ar C = 12 gram/mol
Ar H = 1 gram/mol
Ar O = 16 gram/mol
Mr glokosa (C6H12O6) = (12(6) + 1(12) + 6(16)) = 180 gram/mol
massa glukosa = 0,6 mol × 180 gram/mol
massa glukosa = 108 gram
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